El 21/2/22 a las 12:28, Paul Paulchen escribió:

Hi community,

I was wondering if there is a walk-through for the following issue - or is it even an issue? We got plenty lists with a lot of users come and go from time to time.

Thanks to the thread, I understood how to pick on adress and delete them via the mailman shell; https://lists.mailman3.org/archives/list/mailman-users@mailman3.org/thread/K...

...

...

...

um = getUtility(IUserManager) usr = um.get_user('user@example.com') um.delete_user(usr) commit()

Thanks to this thread, I know how to find the lost souls in our mailman environment https://lists.mailman3.org/archives/list/mailman-users@mailman3.org/thread/R...

...

...

...

um = getUtility(IUserManager) for usr in um.users: ... if len(list(usr.memberships.members)) > 0: ... continue ... adr = usr.addresses[0] ... print(f'Name: {adr.display_name}, Email: {adr.email}, Created: {usr.created_on}')

So I can see them now. Is there a technique, to clean them up? To get rid of them out of the system? I am not a python programmer, but I guess there is a way to use, instead of a single user, a list of users in the delete command of the mailman shell?

e.g. (sorry if this example leads to any pain for any coder/ programmer)

user1@example.com user2@example.com user3@example.com

...

...

...

um = getUtility(IUserManager) usr = um.get_user('user1@example.com','user2@example.com','user3@example.com') um.delete_user(usr) commit()

Hope I made my intention clear. I want to get rid of the users who don't belong/ or are subscribe to a list anymore.

I understand you want this:

https://lists.mailman3.org/archives/list/mailman-users@mailman3.org/message/...

Thanks in advance! Paul

---

Mailman-users mailing list -- mailman-users@mailman3.org To unsubscribe send an email to mailman-users-leave@mailman3.org https://lists.mailman3.org/mailman3/lists/mailman-users.mailman3.org/

On 2/21/22 03:28, Paul Paulchen wrote:

Thanks to this thread, I know how to find the lost souls in our mailman environment https://lists.mailman3.org/archives/list/mailman-users@mailman3.org/thread/R...

...

...

...

um = getUtility(IUserManager) for usr in um.users: ... if len(list(usr.memberships.members)) > 0: ... continue ... adr = usr.addresses[0] ... print(f'Name: {adr.display_name}, Email: {adr.email}, Created: {usr.created_on}')

So I can see them now. Is there a technique, to clean them up? To get rid of them out of the system? I am not a python programmer, but I guess there is a way to use, instead of a single user, a list of users in the delete command of the mailman shell?

The replies by Guillermo and Andrew both point to a message/thread containing the same clean_users.py script. This script will do some of what you want, but maybe not all of it. It will delete Django users who have no corresponding Mailman user or have a corresponding Mailman user that has no role on any list, and optionally delete the Mailman user as well.

What it won't do is delete a Mailman user that has no role on any list if there is no corresponding Django user. For that you would want to add to the above fragment so it becomes:

 >>> um = getUtility(IUserManager)
 >>> for usr in um.users:
...     if len(list(usr.memberships.members)) > 0:
...         continue
...     adr = usr.addresses[0]
...     print(f'Name: {adr.display_name}, Email: {adr.email}, Created: 
{usr.created_on}')
...     um.delete_user(usr)
...     print('    Deleted.)
...
 >>> commit()

-- Mark Sapiro <mark@msapiro.net> The highway is for gamblers, San Francisco Bay Area, California better use your sense - B. Dylan