[MM3-users] Re: How to delete non-users

17 Sep 2022

      Hi Mike,
Yes, the users can be subscribed, but they think that they can't because it seems they are until the moderator accepts them.
I tried your script again, with nothing happening. So I tried this:
...
...
...
a = 1
b = 1
for l in lm:
...     print(a)
...     a = a+1
...     for nm in l.nonmembers.members:
...         print(b)
...         b = b + 1
...         nm.unsubscribe()
...
...
commit()
print(a)
1
print(b)
1
It appears that lm can't see the lists (I have 50+ of them).
Yours,
Allan
On 9/16/22, 15:01 , "Mark Sapiro" <mark@msapiro.net> wrote:
On 9/16/22 11:19, Allan Hansen wrote:
> Hi all,
> 
> This is a bit of an emergency:
> 
> I am getting a bunch of complaints from potential list members of my lists that they can't subscribe and they don't get messages. Apparently, the issue is that they are non-members. I have never created any non-members but looking at the docs it seems that if someone sends a message to the list, they automatically become non-members.
> For individuals I have been able to delete their non-membership and they then could subscribe properly.

I don't understand. the fact that an address is a non-member of a list 
should not impact subscribing that address as a member.

> I have looked at some of my most popular lists and they have hundreds of non-members! It will take me an awful amount of time to remove each one manually, and not doing it - handling each as they complain - is also a lot of waste of time and cause of frustration for all involved.

What is actually happening when the non-member attempts to subscribe as 
a member? What do they do and what it the result?

> I have tried scripting it with delmember, but it does not take the '-r nonmember' option ('findmember'  does!).
> 
> Can anyone help me find out how to
> 	a. delete all non-members of all my lists

If you have access to `mailman shell` you could do:
```
$ mailman shell
Welcome to the GNU Mailman shell
Use commit() to commit changes.
Use abort() to discard changes since the last commit.
Exit with ctrl+D does an implicit commit() but exit() does not.

 >>> lm = getUtility(IListManager)
 >>> for l in lm:
...     for nm in l.nonmembers.members:
...         nm.unsubscribe()
...
 >>> commit()
```

> 	b. prevent MM3 from creating new non-members in the future (so I don't have to keep removing them)

nonmembers are an integral part of Mailman 3's architecture. The basic 
idea is a nonmember has a moderation action and setting a nonmembers 
moderation replaces MM 2.1's adding that address to one of 
*_these_nonmembers (The legacy *_these_nonmembers attributes still 
exist, but only to support regexps).

It would require extensive modification to not create nonmembers. 
However, I still don't understand why the presence of a nonmember record 
is an issue.

-- 
Mark Sapiro &lt;mark@msapiro.net>        The highway is for gamblers,
San Francisco Bay Area, California    better use your sense - B. Dylan
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